The perimeter of a triangle is 69Cm. Side a is 5cm shorter then side b. side c is 5 more than twice side b. Find the length of each side

Step-by-step explanation:

Given parameters:

Perimeter of triangle  = 69cm;

Unknown:

Length of each side  = ?

Solution:

   Side a is 5cm shorter than side b;

         b  = a + 5   i

   Side c is 5 more than twice side b;

          c = 2b + 5

The three sides of triangle are a, b and c;

  Perimeter is the sum of sides of a body;

      a + b + c  = 69

From i;

        a  = b - 5

        b

       c  = 2b + 5

so;

          b - 5 + b + 2b + 5  = 69

           4b = 69

            b  = 17.25cm

a  = b -5  = 17.25 - 5 = 12.25cm

c = 2(17.25) + 5  = 39.5cm

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".