In a sixth grade class the ratio of boys to girls is 4:3 if there are 35 students in the class how many girls are there

The given ratio is 3:4 this means there are 7 people in each unit of this ratio.

It is stated that there are 35 students in total . That would mean that there are

5 Total sets of students in this class . When we multiply the numbers in our starting ratio by this multiple of 5 , our ratio now becomes 15 : 20

15 and 20 do indeed add up to 35 … But , our question wants to know how many more GIRLS are in the class . Boys were calculated to be 15 in number .

Girls were calculated to be 20 in number .

We now know there were 5 more girls than boys in that class ..

5 is your answer .

1.3K views

Vivek Sharma

Answered January 9, 2020

total number of student in class=35

let the number of boys be 3x

let the number of girls be 4x

so therefore 3x+4x=35 =>7x=35 =>x=5

so therefore number of boys in class is 3x=>3(5)=15

and number of girls in class is 4x=>4(5)=20

so there are 20–15=5 more girls in class than boys.

5.3K viewsView 1 Upvoter

Ashis Ghosh, former Retired officer at State Bank of India

Answered April 8, 2019 · Author has 4.4K answers and 931.6K answer views

Let the number boys in the class be b. So b/(35-b)=3:4, or 105-3b=4b, or 7b=105, or b=15. The number of girls in the class is 35-15=20 20-15=5

Ans: there are 5 more girls than the number of boys in the class.

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Sandy Singh

Answered October 27, 2020 · Author has 460 answers and 35.3K answer views

Boys to girls

= 3:4

girls are 4/7

Number of girls

= 4/7*35/1

= 20 girls

class of 35 girls are 20 then boys will be 15 which makes there are 5 more girls than boys

15 views

Wilfred Lalonde, Project Manager (1991-present)

Answered September 20, 2019

5

274 viewsView 1 Upvoter

Maruprolu Venkata Subbareddy

Answered October 11, 2020

Given that,

Total students =35,

Given ratio=3:4,

3+4=7 parts,

7parts=35

1part=?

35/7=5

Diff b/w boys and girls part=1

So ans 5.

33 views

Bruce Conner, former Director of Business Development (Retired) at A Fortune 500 Company (1980-2016)

Answered June 20, 2019 · Author has 471 answers and 198K answer views

5. 3+4=7

35/7=5

5*3 =15 boys

5*4=20 girls

20–15 =5

371 views

Diana Eade

Answered December 2, 2019

5

Add 4+5 =7

35÷7=5

4×5=20 girls

3×5=15 boys

20-15=5 more girls than boys.

236 views

Hungenahalli Sitaramarao Badarinath, Ph.D. in Civil Engineering. Maths keeps one mentally active.

Answered July 14, 2018 · Author has 28.8K answers and 15.5M answer views

The difference of girls to boys = 35(4–3)/(4+3) = 5.

699 views

Hemant Jaishi

Answered May 8, 2020

five more girls are there in the class.

50 views

David Ong

Answered May 10, 2020

15 Boys, 20 Girls (Ratio 3:4)

5.

54 views

Lorine Birir, Admin

Answered January 12, 2020

15 boys and 20 girls this 5 more girls than boys

52 views

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Related Questions

The ratio of boys to girls in a class is 3:2, if there are 12 girls, how many boys are there?

Step-by-step explanation:

17.08

correct me if i am wrong.

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: