Peggy decided to sell brownies and cookies to raise money for her basketball uniform. She sold
brownies for $3.00 and cookies for $2.50. If she
sold 3 fewer cookies than brownies and collected
$218 in all, then how many brownies did she sell?
Write and solve an equation (or a system of
equations) to find your solution.

Peggy sold 41 brownies.

Step-by-step explanation:

She sold three more brownies. 1 brownie cost $3.00, so 3 brownies cost $9.00 because 3×$3.00.

$218-$9 = $209

Figure out the cost of 1 cookie and 1 brownie: $3.00+$2.50=$5.50

$209÷$5.50=38

This means that Peggy sold 38 cookies.

Since she sold 3 more brownies than cookies, add 3 to 38.

3+38=41

So, Peggy sold 41 brownies.

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

step-by-step explanation: