You purchased concentrated cleaner that must be diluted before use. Container a is the cleaner, which is 20% solution. Container b is pure water. You are mixing together the contents of container a and container b to produce 40 gallons of 9% solution. How many gallons from each container are needed to create the 40 gallons of 9% cleaning solution?

18 gallons from container and 22 gallons from the container to be mixed to get the required mixture.

Step-by-step explanation:

Given that the container has 20% concentrated cleaner

and container has pure water which has 0% cleaner.

Let x gallons from container a and y gallons from the container b are mixed to get a 9% concentrated solution.

So,

As the total amount of the final solution= 40 gallons

So,

Using the value of equation (ii) in equation (i), we have

9% of 40 = 20% of x

gallons.

From equation (ii),

18+y=40

gallons.

Hence, 18 gallons from container and 22 gallons from the container to be mixed to get the required mixture.

step-by-step explanation:

i think you should think about the question and not look online.

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.