e length of a rectangle is five times its width. If the area of the rectangle is 320in, find its perimeter.

Step-by-step explanation:

Let width of rectangle =X

So length=5x

Given area of rectangle =320inch

Area of rectangle =length ×width

Length×width=320

5X×X=320

5x^2=320

x^2=320/5

x^2=64

So X=√64

Width x= 8inch

Length 5x=5×8

= 40 inch

Perimeter of rectangle =2(length+width)

=2(40+8)

=2(48)

=96inch

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?