A school group has $140 to spend. Write and solve an inequality that represents the cost to rent the main hall, where h represents the number of hours the group can rent the room.

a. 15h + 40 ≤ 140

b. h ≤ 6.6

Note: The question is missing a table. The table is shown in the attachment below.

Step-by-step explanation:

a. The school group has $140 to spend, and so can only spend an amount less than or equal to $140 when renting the main hall.

The cost of renting the main includes an hourly rate of $15 and a set-up fee of $40.

Let  h represent the number of hours the group can rent the hall.

Cost of renting the main hall, C is given by:

15h + 40 ≤ 140

b. Solution of the inequality:

15h + 40 ≤ 140

15h ≤ 140 - 40

15h ≤ 100

h ≤ 100/15

h ≤ 6.6

Therefore, the main hall can only be rented for a maximum of 6.6 hours or less

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c