Trapezoid QRST with vertices Q(4, -1), R(6, -1), S(8, -6), and T (2, -6): reflected across the line y=x. Where would T' be located?

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

3000000000000000000000

y - 25 = 2 ( x - 10 ) should be the answer