A television newscaster from a 24-hour news station wants to estimate the number of hours per day its viewers watch programming on this channel. The newscaster randomly selects 100 viewers and asks them how many hours
per day they watch this station. The newscaster constructs an 85% confidence interval for the true mean number of
hours viewers watch this station. Which of the following would decrease the margin of error?
using a sample of size 50
O using a sample of size 200
O constructing a 90% confidence interval
O constructing a 95% confidence interval

I’m thinking C

Step-by-step explanation:

eveidence i thing that

step-by-step explanation:

answer:

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

explanation:

service only with 20% tip  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

in the opening of the question the word 'service' is associated only with the pretax value.

the closing part of the question asks: how much did she pay for the  

service

−−−−−−  

so technically the answer is  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

however, the intention of the question provider may have been that your answer is to be  

$

87.12

(

1

+

8

100

)

=

$

94.09

to 2 decimal places.

'

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

tony b

mar 21, 2017

answer:

trying to explain it another way

explanation:

service charge  

.

→

$

72.60

20% tip  

20

100

×

$

72.60

=

$

14.52

−−−−−−  

←

add

$

87.12

tax  

8

100

×

$

87.12

=

$

6.97

−−−−−  

←

add

$

94.09

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