Given: a-b= c-d, b=d-1, c=6; prove: a=5

Given :

a-b = c-d    ...1)

b = d-1       ...2)

c = 6

To Prove :

a = 5

Solution :

Adding equation 1 and 2, we get :

(a-b) + (b) = (c-d) + (d-1)

a = c -1   ...3)

Putting given value of c = 6 in above equation, we get :

a = 6 - 1

a = 5

Hence, proved.

answer: it actually depends on which is the independent variable and which is the dependent variable. let us say we're looking at a linear equation. y=2x+3. we theoretically could switch the equation to be x=(y-3)/2 and it would be the same line. so either a causes b or it can be that b causes a. so technically the answer is false

step-by-step explanation:

2+2 obliviously is 4.