What is the slope of a line passing
through points (-6, 3) and (-3, -1)?

-4/3

Step-by-step explanation:

you do change in y over change in x which is -1-3 over -3-(-6)

when you do the calculations you get -4/3

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

1. minimum

2. 6400

3. eight

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