![\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}\\\\6(x^2-3x+2)\ne0\ \iff\ x=\frac{3\pm\sqrt{9-8}}{2}\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\\\\\\\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}=\dfrac{x(5x^2-8x-4)}{6(x^2-3x+2)}=\dfrac{x(5x^2-10x+2x-4)}{6(x^2-2x-x+2)}=\\\\\\=\dfrac{x[5x(x-2)+2(x-2)]}{6[x(x-2)-(x-2)]} =\dfrac{x(x-2)(5x+2)}{6(x-2)(x-1)}=\dfrac{x(5x+2)}{6(x-1)}=\dfrac{5x^2+2x}{6x-6}\\\\\\f(x)=5x^2+2x\\\\g(x)=6x-6](/tpl/images/0877/1916/f3149.png)
Simplify the expression
...
Answers: 3
Another question on Mathematics
Mathematics, 20.06.2019 18:02
Z4=289 there should be 4 answers total 2 whole numbers and either 2square root or imaginary number answers
Answers: 1
Mathematics, 21.06.2019 12:50
G(x)=x2-16xb=-16, so =16 = 649(x) = (x2 - 16x + 64) - 649(x) = (x - 1)2-
Answers: 1
Mathematics, 21.06.2019 18:00
Ling listed all of the factors of a mystery number: 1,2,4,8,16,32 what is the mystery number?
Answers: 2
You know the right answer?
Questions
Health, 05.10.2019 20:30
Biology, 05.10.2019 20:30
History, 05.10.2019 20:30
Arts, 05.10.2019 20:30
Mathematics, 05.10.2019 20:30
Mathematics, 05.10.2019 20:30
Biology, 05.10.2019 20:30
History, 05.10.2019 20:30
