A fair coin is tossed three times in succession. The set of equally likely outcomes is {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}. Find the probability of getting exactly two heads out of three tosses.

If a fair coin is tossed three times, sample = 2^3 = 8 (hhh, hht, hth, thh, htt, tht, tth, ttt) where h=head and t=tail.

Probability of getting one:

Outcomes with one head (h) = 3

P(1 h) = 3/8 = 0.375

Step-by-step explanation:

i think the answer is d im not sure