How is an equation of the line that passes through the point (2,3) and has a slope of -6 written?

y - 3 = -6 (x-2) or y = -6x + 15

Step-by-step explanation:

y-k = m (x-h)

substitute (2,3) for (h,k):

y-3 = m (x-2)

substitute -6 for m:

y - 3 = -6 (x-2)

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph