18. The area of the rectangle shown is at most 140 square centimeters.
a. Write and solve an inequality to find the possible
values of x.
10 cm
b. Based on the answer in part (a), is it possible for
the rectangle to have a length of 15 centimeters?
Explain.
(3x + 2) cm

9514 1404 393

  a) 10(3x+2) ≤ 140; x ≤ 4

  b) no

Step-by-step explanation:

a) The area is the product of length and width. We want that product to be no greater than 140:

  10(3x +2) ≤ 140 . . . . your inequality

We can solve this by dividing by 10 first.

  3x +2 ≤ 14

  3x ≤ 12 . . . . . . subtract 2

  x ≤ 4 . . . . . . . . divide by 3; the solution to the inequality

__

b) If the length were 15, the area would be 10×15 = 150, which is greater than 140. The length cannot be 15 if the area is at most 140.

the answer is 37

step-by-step explanation:

x = -2

y = 848

step-by-step explanation:

plug in the numbers