The graph of a linear function f passes through the point (-1,9) and has a slope of -3. what is the zero of f? answer choices:
-6
4
2
-2

x=2 (third option)

Step-by-step explanation:

Equation of a line

Being m is the slope and (h,k) is a point through which the line passes, the point-slope form of the equation of a line is:

y - k = m ( x - h )

We have the function f passes through the point (-1,9) and has a slope of m=-3. The point-slope equation of the line is:

y - 9 = -3 ( x - (-1) )

Operating:

y - 9 = -3 ( x + 1 )

y - 9 = -3x - 3

Adding 9:

y = -3x + 6

To calculate the zero of the function we set y=0 and solve for x:

-3x + 6 = 0

Subtracting 6:

-3x = - 6

Dividing by -3

x = - 6 / ( - 3 )

x = 2

x=2 (third option)

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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