Acoffee mixture has beans that sell for $0.20 a pound and beans that sell for $0.68. if 120 pounds of beans create a mixture worth $0.54 a pound, how much of each bean is used? model the scenario then solve it. then, in two or more sentences explain whether your solution is or is not reasonable.

Let x be the amount of beans in mixture for $0.20 a pound  and y be the amount of beans in mixture for $0.68 a pound.  If 120 pounds of beans create a mixture, then

x+y=120.

x pounds beans for $0.20 a pound  cost $0.20x and y pounds beans for $0.68 a pound cost $0.68y. If mixture worth $0.54 a pound, then it costs $0.54·120=$64.8 for 120 pounds. Then

0.20x+0.68y=64.8

You get the system of equations:

Solve it.

1. Multiply second equation by 100:

2. Express x from first equation and substitute it in second:

3. The equation 20(120-y)+68y=6480 contains only y and is easy to solve:

2400-20y+68y=6480,

48y=6480-2400,

48y=4080,

y=85.

4. Then x=120-y=120-85=35.

you should take 35 pounds of beans for $0.20 a pound  and 85 pounds of beans for $0.68 a pound.

i dont know and i dont care for math bc it is a stupied subject

step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.