The sum of two consecutive integers is 41. What are the two integers?

Step-by-step explanation:

Let the smaller of two consecutive integer be x therefore other integer is x+ 1

As per statement the sum of two consecutive integers is 41. To find out the integers.

x + (x + 1) = 41

x + x + 1 = 41

2x + 1 = 41

2x = 41 - 1

2x = 40

x = 40/2

x = 20

The smaller of two consecutive integers is 20, thus other integer is x + 1 = 20 + 1 = 21

The two consecutive integers are 20 and 21

Answer the two consecutive integers are 20 and 21

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)