What if you had two types of grape drink, one with 5% real fruit juice and another with 10% real fruit juice? Suppose you wanted a gallon of grape drink with 6% real fruit juice. How much of the 5% drink and how much of the 10% drink should you mix together to produce it?

10.20(20−n)+6.8nNow solve for n:204−10.20n+6.8n204−3.4n−3.4nn=170=0170Distributive Property=170Add like terms.=−34 Subtract 204.=10 Divide by −3.4.

Since n=10, we can plug that into m+n=20.

m+10=20⇒m=10.

The coffee company needs to use 10 pounds of each type of coffee in order to have a 20 pound mixture that costs $8.50 per pound.

Step-by-step explanation: this might be wrote 3 times

answer: ask

step-by-step explanation:

6mm^3 or .6cm^3

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      /   \

  36     6

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6     6   6

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