Which equation is perpendicular to the graph of 5x - 3y = 12

y = -3/5x + c

Step-by-step explanation:

Re-arrange the initial equation so that the it becomes y =

To do this, you +3y on both sides to get 5x = 3y + 12

And then -12 on both sides to get 5x - 12 = 3y

Divide everything by 3 so you get 5/3x - 4 = y OR y = 5/3x - 4

The gradient of the initial equation is 5/3, to find the perpendicular line, you need the negative reciprocal of it, which is -3/5

Therefore your perpendicular line should be y = -3/5x + c

Because you didn't specify on what point they intersect, i can't find c for you.