Write an equation for the line that passes through (4,10) and is perpendicular to the line 6x-3y=5

y =  x + 12

Step-by-step explanation:

Given expressions:

           Coordinates = (4,10)

  Equation of the line;  6x - 3y = 5

Unknown:

Equation of the line perpendicular = ?

Solution:

 A line perpendicular to the given one will have a negative inverse slope.

  Equation of any given line is expressed as:

              y  = mx + c

y and x are the coordinates

 m is the slope

 c is the intercept

             Now; re-write 6x-3y = 5 in the form y= mx + c and find the slope;

   6x - 3y = 5

          -3y = 5- 6x

            y = + 2x

The slope of a perpendicular line will be

Also, let us find the y-intercept, c;

         y  = mx + c

         10 =   x 4 + c

       10 = -2 + c

         c  = 12

The equation of the new line is ;

        y =  x + 12

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval