find specified geometric series of the following geometric sequences of 3, 12, 48,... S7 with solution?

Step-by-step explanation:

The formula for fundung the nth term of t geometeric series is expressed as;

Tn = ar^(n-1)

a is the first term

n is the number of term

r is the common ratio

Given

a = 3

r = 21/3 = 48/12 = 4

Substitute

Tn = 3(4)^(n-1)

Tn = 3(4^n/4)

Tn = 3/4(4^n)

Tn = 0.75(4^n)

Hence the nth term of the geometric series is Tn = 0.75(4^n)

To get any term, simply substitute the value of into the equation

answer: median

step-by-step explanation:

the median is the middle value when a data set is ordered from least to greatest

ιт ιѕ:

125.28

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