The sum of three numbers is 12 . The sum of twice the first number, 3 times the second number, and 4 times the third number is 37 . The difference between 7 times the first number and the second number is 25. Find the three numbers.

Given:

The sum of three numbers is 12 .

The sum of twice the first number, 3 times the second number, and 4 times the third number is 37 .

The difference between 7 times the first number and the second number is 25.

To find:

The three number.

Solution:

Let the three numbers are x, y and z respectively.

According to the question,

          ...(i)

        ...(ii)

          ...(iii)

From (iii), we get

Put value in (i).

       ...(iv)

Put value in (ii).

         ...(v)

Now, Multiply equation (iv) by 4 and subtract the result from (v).

Put x=4 in (iv).

Put x=4 in .

Therefore, the three numbers are 4, 3 and 5 respectively.

d≈7.07in

step-by-step explanation:

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation: