A researcher wishes to estimate, with % confidence, the population proportion of adults who eat fast food four to six times per week. Her estimate must be accurate within % of the population proportion.

The minimum sample size required is 1068.

Step-by-step explanation:

The complete question is:

A researcher wishes to estimate, with 95%  confidence, the population proportion of adults who eat fast food four to six times per week. Her estimate must be accurate within 3%  of the population proportion.

No preliminary estimate is available. Find the minimum sample size needed.

Solution:

The (1 - α)% confidence interval for the population proportion is:

The margin of error for this interval is:

The information provided is:

Assume that the sample proportion is 50%.

The critical value of z is, 1.96.

Compute the minimum sample size required as follows:

Thus, the minimum sample size required is 1068.

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05

0.32

step-by-step explanation:

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