The probability that a house in an urban area will develop a leak is 2%. If 21 houses are randomly selected, what is the probability that none of the houses will develop a leak?

The probability that none of the houses will develop a leak is 0.6543.

Step-by-step explanation:

Let X denote the number of houses in an urban area that develop a leak.

The probability that a house in an urban area will develop a leak is, p = 0.02.

A random sample of n = 21 houses are selected.

Every house is independent of developing a leak.

Thus, the random variable X follows a binomial distribution with parameters n = 21 and p = 0.02.

Compute the probability that none of the houses will develop a leak as follows:

Thus, the probability that none of the houses will develop a leak is 0.6543.

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

asdfghkl

step-by-step explanation:

asdfghkl