The ratio of the perimeter of triangle PQR to the perimeter of rectangle ABCD is 5 : 9. All in centimeters, Triangle (sides) PQ: (x-3) PR: (3x-5) QR: (4x+3), Rectangle (sides) AB: (2x+2) BC: (4x - 1/2) [AB is longer than BC a. Write algebraic expressions for the perimeters of triangle PQR and rectangle ABCD.
b. Write a linear equation using the algebraic expressions written in part a. Then solve for x.
c. Find the area of rectangle ABCD.

A) 20 in

B) 26 in and it got bigger by 1.3 times

C) 40 in and it got bigger by 2 times

Step-by-step explanation:

A) so the formula for finding perimeter is P= 2(L+W) so its (3+7)*2 = 20

B) if you double 3, 3*2=6 then it is 2*(6+7) = 26. 26/20= 13/20= 1.3 times more

C) if you double 3, 3*2=6 and 7, 7*2= 14 then it is (14+6)*2 = 40. 40/20=2/1 = 2 times more.

Also i couldnt solve D for you but try to solve it using what I wrote below.

Hope it helps :)

[ (x-3) + (3x-5) + (4x+3) ] : [2(2x+2)+ 2(4x - 1/2) ] = 4 : 9

(8x-5) / (12x+3) = 4/9

Step-by-step explanation: