Mel spent $43.97 on three cds. Who are the CDs were the same price, and the third CD cost $5.00 more than one of the other two CDs. The total cost can be represented by the equation 2c + (c+5)= 43.97, where c is the cost of one lower priced CD. What was the cost of the higher priced CD? A.$11.28
B.$12.99
C.$14.66
D.$17.99

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.

2/3(-6y+9x) expand each expression using the distributive property

Rewrite so the subject can be y in the formula d=m-y/y+n