the length of the rectangular field is 7 times of its breadth its area is 1792 square metres find the cost of fencing it at the rate of rupees 1.5 per metre

Step-by-step explanation:

first you would need to find the perimeter in order to find the cost of fencing.

x(7x)=1792

7x^2=1792

x^2=256

x=16

so you have x which is the width. now time to find the length

16 times 7 is 112

112 is your width

112+112+16+16 is 256, which is your perimeter.

256 times 1.5 is your cost, or 384 rupees

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0