Find the probability that a fisherman selected at random fishing from shore catches one or more fish in a 6-hour period.

Complete Question

The percentages of fishermen who caught x fish in a 6-hour period while fishing from shore is

   X                       0                      1                   2                    3               4 or more

  probability         43% (0.43)   36%(0.36)    14%(0.14)      6%(0.06)    1%(0.01)

Find the probability that a fisherman selected at random fishing from shore catches one or more fish in a 6-hour period

The probability is  

Step-by-step explanation:

Generally the probability that a fisherman selected at random fishing from shore catches one or more fish in a 6-hour period is mathematically represented as

=>  

=>  

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3