Records show that Oliver is typically 10–30 minutes late for his shift at work. The distribution for the minutes he is late forms a consistent pattern, which can be graphed as the given uniform density curve. A uniform density curve is at y = startFraction 1 Over 20 EndFraction from 10 to 30.

What percentage of the time will Oliver arrive between 15 and 20 minutes late to work?

5%
16.7%
25%
50%

I believe its C- 25%

Step-by-step explanation:

If you count how far it is from 15 to 20 (5) and divide that by 1/20 you should end up with 0.25. Turn that into a percent and you get 25%.

Let me know if Im wrong!

725 parts per hour.

step-by-step explanation:

hi there, this answer is actually really simple.

you can set it up as 1450/2 or 3625/5 to find the answer.

they want to know how much per hour is being made, so you just divide.

1450/2=725.

and that's how many are produced per hour.

hope this . : )

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70