PLEASE HELP QUICK On a dark and stormy night, Snoopy suddenly saw a flash of lightning. Ten seconds later he heard the sound of thunder. The speed of sound is $1088$ feet per second and one mile is $5280$ feet. Estimate, to the nearest half-mile, how far Snoopy was from the flash of lightning.

Around 2 miles

Step-by-step explanation:

Given that the speed of light in this problem travels at 1088 feet per second, with a mile being 5280 feet. If Snoopy heard the sound of thunder 10 seconds later, then snoopy is 10880 feet away or 10880/5280 = 2.0606... ≈ 2 miles.

This is done using the formula for speed which is. s = d/t ; speed = distance divided by time.

To find the distance, rearrange the formula by multiplying time on each side so that we are solving for distance.

s = d/t

×t ×t

(cancels the denominator of t in d/t)

s × t = d / t × t

st = d

(symmetric property of equality)

d = st ; distance = speed × time.

now that we have this formula, just multiply the speed of light, and the time it took for Snoopy to hear the thunder.

Distance = 1088ft/s × 10s = 1088ft × 10 (seconds cancel) = 10880ft.

The final step to finding the milage is converting this measurement of feet into miles by dividing by 5280 as stated in the problem.

So 10880ft/5280ft = 2 R(remainder) 320 ft = 2 + 320 / 5280 = 2 + 6/99 = 2 + 0.0606... = 2.0606... ≈ 2

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: