Tammy has a rectangular rug with an area of 21 square feet. The rug is 4 feet longer than it is wide. Part A: Create an equation to determine the length and the width of the rug.
Part B: Use your equation from Part A to solve for the length and width of the rug. Show your work.

A) A = W(W + 4)

B) Length = 7 ft

Width = 3 ft

Step-by-step explanation:

A) Let the length and width of the rectangular rug be L and W respectively.

We are told that the rug is 4 feet longer than it is wide. Thus;

L = (W + 4)

Also we are told that the area is 21 ft²

Now, formula for area of a rectangle is;

A = LW.

Thus;

A = W(W + 4)

21 = W(W + 4)

B) 21 = W² + 4W

W² + 4W - 21 = 0

Using quadratic formula to find the roots, we arrive at W = 3 ft.

Thus, L = 3 + 4 = 7 ft

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c