Solve the problem involving consecutive integers. If three times the smaller of two consecutive integers is added to four times the larger, the result is 109. Find the smaller integer.
A. 14 B. 45 C. 15 D. 16

c.15

Step-by-step explanation:

smaller integer=x

larger integer=x+1

3x+4(x+1)=109

3x+4x+4=109

7x+4=109

7x=105

x=105/7

x=15

check:

3(15)+4(15+1)=109

45+64=109

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