When Adrian runs the 400 meter dash, his finishing times are normally distributed with a mean of 77 seconds and a standard deviation of 3 seconds. What is the probability that in a given race, his finishing time will be faster than 75 seconds, to the nearest thousandth?

0.749

Step-by-step explanation:

We start by calculating the z-score

Mathematically:

z-score = (x-mean)/SD

z-score = (75-77)/3 = -2/3 = -0.67

The probability we want to calculate is;

P( X > -0.67)

we can use the standard normal distribution table for this

Using this table, the probability has a value 0.74857 which is 0.749 to the nearest thousandth

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}