Each year, a car loses 25% of the value it had the previous year. If the value of a car is $12,500 during the first year it is owned, which function represents the value of the car after y years

T=12500-0.25y

Step-by-step explanation:

Step one:

given data

The value of the car is $12500.

let the value of the previous year be T

let the number of years be y

25% will be 0.25this is equivalent to the gradient

The expression for the change in price can be represented linearly using the equation of a straight line,

y=mx+c

but since the price is reducing the expression becomes

y=-mx+c

Now, in this situation the expression for the cost after y years is

T=-(0.25y)+12500

rearrange

T=12500-0.25y

The expression is T=12500-0.25y

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

9x