A. {[(-15+5)×2+8]-32÷8}-(-7) b. (5-2)³×2+[-4+(-7)]÷(-2+4)²

c. {-10-[12+(-3)²] + 3³}+3³}÷(-3)

I'll mark you brainliest if you solve these with explanation

Step-by-step explanation:

The answers are:

A)  {[(-15+5)×2+8]-32÷8}-(-7)

Calculate within parentheses: -16 - (-7)

Add and subtract (left to right): -16 - (-7) = -9

B) (5-2)³×2+[-4+(-7)]÷(-2+4)²

To solve this problem, you need to follow the steps of order of operations.

Calculate within parentheses: * 2 + [-4 + (-7)] ÷ (-2+4)²

Calculate within parentheses: *2 -11 ÷ (-2+4)²

Calculate within parentheses: 27 × 2 - 11 ÷ (-2+4)²

Calculate exponents: 27 × 2 -11 ÷ 4

Multiply and divide: 54 - 11 ÷ 4

Multiply and divide: 54 -

Add and Subtract:  

Convert improper fractions to mixed numbers: =

C) {-10-[12+(-3)²] + 3³}+3³}÷(-3)

Calculate within parentheses: -4 ÷ (-3)

Multiply and divide:  

Simplify and convert improper fraction to a mixed number:

= =

Hope this helped! If so, please mark brainliest.

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40