Applicants to a psychology department have normally distributed GRE scores with a mean, LaTeX: \muμ, of 544 and a standard deviation, LaTeX: \sigmaÏ, of 103. What percentage of applicants scored between 500 and 700? Round to the nearest percent. A. -24% B. 78% C. 2296 D. 24% E. 5%

The probability is P(500 < X  < 700 ) =  0.60044

Step-by-step explanation:

From the question we are told that

    The mean is  

     The standard deviation is  

Generally the percentage of applicant that scored between 500 and 700 is mathematically represented as

=>  

Generally from the z-table, the area under the normal curve to the left corresponding to    1.5146 and     -0.4272  is

  P(  Z<  1.5146 )  =  0.93506

   P ( Z <   -0.4272 ) = 0.33462

So

       P(500 < X  < 700 ) =  0.93506 -  0.33462

=>    P(500 < X  < 700 ) =  0.60044

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

3 is greater then both of those numbers