Suppose the amount of a popular sport drink in bottles leaving the filling machine has a normal distribution with mean 101.5 milliliters (mL) and standard deviation 1.6. If 36 bottles are randomly selected, find the probability that the mean content is less than 102.1 mL

0.98778

Step-by-step explanation:

When we are given a random number rod samples, we solve using z score formula

z = (x-μ)/σ/√n, where

x is the raw score = 102.1 mL

μ is the population mean = 101.5 milliliters (mL)

σ is the population standard deviation = 1.6.

n = 36

z = 102.1 - 101.5/1.6/√36

z =2.25

Probability value from Z-Table:

P(x<102.1) = 0.98778

Hence, If 36 bottles are randomly selected, find the probability that the mean content is less than 102.1 mL is 0.98778

answer: 193

explanation:

200-7 = 193