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Mathematics, 21.06.2019 19:50
Prove (a) cosh2(x) ā sinh2(x) = 1 and (b) 1 ā tanh 2(x) = sech 2(x). solution (a) cosh2(x) ā sinh2(x) = ex + eāx 2 2 ā 2 = e2x + 2 + eā2x 4 ā = 4 = . (b) we start with the identity proved in part (a): cosh2(x) ā sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 ā sinh2(x) cosh2(x) = 1 or 1 ā tanh 2(x) = .
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Mathematics, 22.06.2019 00:30
Consider this expression and the steps to evaluate it. 4^5(ā2)^9/4^8(ā2)^3 1. apply the quotient of powers: āāāā (ā2)^a/4^b 2. evaluate powers: āāāāāāāāā c/d select the value of each variable. a = _ b = _ c = _ d = _
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Mathematics, 22.06.2019 02:00
If the angle bisectors of a pair of opposite angles of a quadrilateral are the opposite sides of a parallelogram formed by the two angle bisectors and two sides of the quadrilateral, is the quadrilateral always a parallelogram? explain your answer.
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