4.5.36 A smoke jumper jumps from a plane that is 1500 ft above the ground. The function h= -16? + 1500 gives the jumper's height hin feet during the free fall att seconds
a. How long is the jumper in free fall if the parachute opens at 1000 ft?
b. How long is the jumper in free fall if the parachute opens at 940 ft?
c. What is a reasonable domain and range for the function h? no

Step-by-step explanation:

Given function is h(t) = -16t² + 1500

a). For h(t) = 1000 feet,

   1000 = -16t² + 1500

   1000 - 1500 = -16t² + 1500 - 1500

   -500 = -16t²

    t² =

    t =

    t = 5.59 sec

b). For h(t) = 940 feet,

   940 = -16t² + 1500

   940 - 1500 = -16t² + 1500 - 1500

   -16t² = -560

   t² =

   t =

   t = 5.92 sec

c). For domain and range of the function,

  When the jumper comes down to the ground,

   h = 0

   0 =-16t² + 1500

   t² =

   t =

   t = 9.68 sec

  Since, x-values on the graph vary from x = 0 to x = 9.68,

  Domain : [0, 9.68]

  Vertex of the quadratic function: (0, 1500)

  Since, coefficient of the highest degree term is negative, parabola will open downwards.

  Therefore, y-values of the function will vary in the interval y = 0 to y = 1500

  Range: [0, 1500]  

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

21

step-by-step explanation: