Question in pic. please help!

Arranging from longest (at top) to shortest (at bottom)

DF

EF

DE

Step-by-step explanation:

We need to place the sides of triangle DE, DF and EF from longest to shortest.

The triangle has longest side that is opposite to the largest angle

We know two angles < E= 61° , <F= 59° we need to find <D

Sum of angles of triangle = 180°

So, 61°+59°+<D=180°

120°+<D=180°

<D=180°-120°

<D=60°

So, the largest angle is <E= 61°

The longest side must be opposite to <E so, the side is DF

The second largest angle is <D=60° so, second side will be EF

The smallest angle is <F=59° so, third (shortest) side will be DE

Arranging from longest (at top) to shortest (at bottom)

DF

EF

DE

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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