2. Look at the way the following exponential equation was solved for x. Somewhere in the steps, an error was made. Equation: 5^x-4 = (1/125)^2x+1. Steps: 1: 5^x-4 = (5^3)^2x+1. 2: 5^x-4 = 5^6x+3. 3: x-4=6x+3. 4: -5x -4 = 3. 5: -5x=7. 6: x = -7/5. a. Where was the error made? Pick one: From Step 1 to 2. From Step 2 to 3. From Step 3 to 4. From Step 4 to 5. From Step 5 to 6. Write the specific part of the problem that is wrong here: b. Explain why it is a mistake and what should be done instead. c. Work out the rest of the problem correctly, showing your work step by step.

Let's solve 5\cdot 2^x=2405⋅2

Let's solve 5\cdot 2^x=2405⋅2 x

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned}

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x =240

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x =240=48

Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x =240=48

a c

step-by-step explanation:

you just switch the numbers basically so it would be 3/17