Given that sec(0) =25/7
and 0 is in Quadrant I, find csc(0) and tan(0).

Csc(0)=24/27 and Tan(0)= 24/7

Step-by-step explanation:

We know that secant is the inverse of cos. So that Sec(x) = Cos^-1(x)= hypotenuse/adjacent. We now know that 25 is hypotenuse and 7 is the length of side adjacent to angle theta.

Given this information we can find the length of side opposite to theta, which has length 24.

Now we know:

Hypotenuse=27

Adjacent=7

Opposite=24

Csc is inverse of sin, so that scs=sin^-1=hypotenuse/opposite=27/24

and tan=opposite/adjacent=24/7

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,