Mathematics, 12.11.2020 17:10 haylie1456

El 10% de los huevos de un supermercado están rotos, haya la probabilidad de que un cliente que compra media docena de huevos encuentre como mucho un huevo roto

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Answer from: coryintheswamp

La probabilidad de encontrar como mucho un huevo roto es 0,8857.

Step-by-step explanation:

Podemos calcular la probabilidad de econtrar un huevo roto usando la ecuación de distribución binomial:

$P (x) = \left(\begin{array}{c}n&x\end{array}\right)p^{x}(1 - p)^{n-x}$

En donde:

p: es la probablidad de encontrar huevos rotos = 10% = 0,1

x: es el número de éxitos

n: es el número de ensayos = 6 (media docena de huevos)

Ahora, como nos piden la probabilidad de enontrar como mucho un huevo roto, esto quiere decir que debemos encontar la suma de la probablidad de encontar un huevo roto con la probabilidad de encontrar ninguno roto:

P = P(0) + P(1)

$P = \left(\begin{array}{c}6&0\end{array}\right)0,1^{0}(1 - 0,1)^{6-0} + \left(\begin{array}{c}6&1\end{array}\right)0,1^{1}(1 - 0,1)^{6-1} = 0,5314 + 0,3543 = 0,8857$

Entonces, la probabilidad de encontrar como mucho un huevo roto es 0,8857.

Espero que te sea de utilidad!

Answer from: Quest

think the answer would beb

Answer from: Quest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

4 simplify \frac{5}{6}x

x to \frac{5x}{6}

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

5 convert 1\frac{1}{3}1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

1×3+1

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3+1

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

to \frac{13.75}{3}+\frac{4x}{3}

13.75

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

13.75

9 simplify \frac{13.75}{3}

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

−4.583333

11 simplify \frac{71}{12}-4.583333

−4.583333 to \frac{4}{3}

\frac{4x}{3}=\frac{4}{3}

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

×3

13 simplify \frac{4}{3}\times 3

×3 to \frac{12}{3}

4x=\frac{12}{3}4x=

14 simplify \frac{12}{3}

to 44

4x=44x=4

15 divide both sides by 44

x=1

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