(please help) Consider the system of inequalities and its graph.

y ≥

y ≤ x – 3

On a coordinate plane, 2 solid straight lines are shown. The first line has a positive slope and goes through (negative 8, negative 2) and (0, 0). Everything above the line is shaded. The second line has a positive slope and goes through (0, negative 3) and (3, 0). Everything to the right of the line is shaded. The section in quadrant 1 is labeled 3, the section in quadrant 2 is labeled 2, the section in quadrant 3 is labeled 1, and the section in quadrant 4 is labeled 4.
In which section of the graph does the actual solution to the system lie?

1
2
3
4

your answer is b.

step-by-step explanation:

the 2 points are: (3,1) and (6,6)

first, let's find the slope:

(6-1)/(6-3) = 5/3

then let's plug this into the point-slope formula:

y - 1 = 5/3(x - 3)

this is your answer! the below is just the simplified form.

y - 1 = 5/3x - 5

y = 5/3x - 4

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students link these representations.

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