Find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 70

9, 11 and 13

Step-by-step explanation:

Let the integers be x, x + 2, x + 4.

x + 2(x + 2) + 3(x + 4) = 70

x + 2x + 4 + 3x + 12 = 70

6x = 54

x = 9

therefore the three integers are 9, 11 and 13

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false

step-by-step explanation:

the reason i say this is because for a certain length of sides you can pick any two and the length is wither equal or greater than the third side and in this case it's not.

3 + 5 = 8

8 is smaller than 9 which is the third side.

hope this : )