Tom has $5.05 in quarters and dimes. How many coins are quarters if the total number of coins is 28? Try creating a system of equations and solving this by either
substitution or elimination.
quarters

Help due by 8 am tm

15 quarters

Step-by-step explanation:

Assuming q = quarters and d = dimes...

First, set up the equations. q + d = 28 since we have 28 coins, and the latter is because a quarter is worth $0.25 and a dime is worth $0.1 - totaling $5.05.

q + d = 28

.25q + .10d = 5.05

Try to get one of the variables equal to the equation above. In this case, I tried to get the "q" variables equal to each other.

q + d = 28

4(.25q + .10d) = 4(5.05)

After this, you "subtract" the two equations from each other. Remember that d = 1d, and 1 - .4 = .6

q + d = 28

q + .4d = 20.20

Divide both sides by .6 to get d by itself.

.6d = 7.8

There are 13 dimes.

d = 13

Subtract 13 from the total coins (28) to get the amount of quarters.

28 - 13 = 15

13 dimes, 15 quarters. Hope this helped!

you can't solve x because it is 2 linear equation and you only have one equation