How would you describe the relationship between the real zero(s) and x-intercept(s) of the function f(x) =
3x(x - 1)
x2(x+3)(x + 1)
When you set the function equal to zero, the solution is x = 1; therefore, the graph has an x-intercept of (1,0).
O When you set the function equal to zero, the solutions are x = 0 or x = 1; therefore, the graph has x-intercepts at
(0, 0) and (1,0).
O When you substitute x = 0 into the function, there is no solution, therefore, the graph will not have any X-
intercepts.
Since there are asymptotes at x = -3, x = -1, and x = 0, the graph has no x-intercepts and therefore, no real
zeros.