Can anyone help me with this algebra problem ?

y=mx+b is the form in which these equations are. B represents the y intercept and M is the slope

currently to find slope we need to get y alone on the left side of the equation for all the answers:

A.y-4=3(x-2) > y-4=3x-6 (i also distributed) > y=3x-2

B.  y+4=-3(x+2)> y+4=-3x-6 > y=-3x-10

C. y-2=-3(x-4) > y-2=-3x+12 > y=-3x+14

D. y-4= -3( x-2) > y-4= -3x+6 > y=-3x+10

All of these equations except A have a slope of -3 so A is already out and to find which one is valid we need to plug in the point (2, 4) for each of the equations

B. 4=-3(2)-10 > 4=-6-10> 4=-16- not valid

C. 4 =-3(2)+14 >  4=-6+14>4=8 not valid

D. 4=-3(2)+10 >4=-6+10 > 4=4 - Valid

Only D is correct

Step-by-step explanation:

4.08%

step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,