The sum of two real numbers is 8 and their product is 14. What is the sum of their reciprocals?

Step-by-step explanation:Let our two numbers be  a  and  b . Then we can see that  a+b=8  and  ab=15 . Now consider

(a+b)3=a3+3a2b+3ab2+b3  by the binomial expansion. Now we have all the information to solve this, observe since  a+b=8  and  ab=15 . We have

(8)3=a3+3ab(a)+3ab(b)+b3  

a3+b3+3ab(a)+3ab(b)=83  

a3+b3+3ab(a+b)=83  

a3+b3=83−3ab(a+b)  

a3+b3=83−3(15)(8)=512−360=152  

You can also observe that  3  and  5  fulfill those conditions so, then  33+53=27+125=152 . Which is our result.

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.