How to find vertex form with vertex: (3,6) and y intercept: 2

Step-by-step explanation:

The vertex form of  the equation of the parabola with vertex (h, k)  is:

f(x) = a(x - h)² + k

So for vertex (3, 6) it will be:

f(x) = a(x - 3)² + 6

y intercept: 2 means  f(0) = 2

f(0) = a(0 - 3)² + 6

2 = a(-3)² + 6

2 -6 = 9a + 6 -6

-4 = 9a

a = ⁻⁴/₉

Therefore:

The vertex form of quardatic function with vertex: (3,6) and y intercept: 2 is

                             f(x) = - ⁴/₉(x - 3)² + 6

step-by-step explanation:

4tyuiuygsugv15167889997q669a

xcvb nm you ugly

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.